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Solution set of 6x2 + x - 15 = 0 is

  • a)
    {5/3, 3/2}

  • b)
    (-5/3, -3/2}

  • c)
    {5/3, 7/2}

  • d)
    {-5/3, 3/2}

Correct answer is option 'D'. Can you explain this answer?
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Solution set of 6x2 + x - 15 = 0 isa){5/3, 3/2}b)(-5/3, -3/2}c){5/3, 7...
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Solution set of 6x2 + x - 15 = 0 isa){5/3, 3/2}b)(-5/3, -3/2}c){5/3, 7...
Analysis of the Quadratic Equation:
The given quadratic equation is 6x^2 + x - 15 = 0.

Finding the Solution Set:
To find the solution set of the quadratic equation, we can either factorize the equation or use the quadratic formula.

Factoring Method:
We can factorize the quadratic equation as follows:
6x^2 + x - 15 = 0
6x^2 + 10x - 9x - 15 = 0
2x(3x + 5) - 3(3x + 5) = 0
(2x - 3)(3x + 5) = 0
Setting each factor to zero, we get:
2x - 3 = 0 or 3x + 5 = 0
2x = 3 or 3x = -5
x = 3/2 or x = -5/3
Therefore, the solution set is {3/2, -5/3}.

Using Quadratic Formula:
Alternatively, we can use the quadratic formula to find the solution set:
For the quadratic equation ax^2 + bx + c = 0, the quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 6, b = 1, and c = -15. Plugging these values into the formula, we get:
x = (-1 ± √(1^2 - 4*6*(-15))) / 2*6
x = (-1 ± √(1 + 360)) / 12
x = (-1 ± √361) / 12
x = (-1 ± 19) / 12
Therefore, x = (18 / 12) or x = (-20 / 12), which simplifies to x = 3/2 or x = -5/3.

Conclusion:
The solution set of the quadratic equation 6x^2 + x - 15 = 0 is {3/2, -5/3}. Therefore, the correct answer is option 'D' {9, -10}.
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